Algebra Word Problem

A rectangle's length is 8 cm more than three times it's width. If the perimeter is 128 cm, find the length and width. What is the equation for this?

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  1. You need to sove two simultaneous equations.

    L = length W = width

    L = 3W + 8
    2(L + W) = 128

    Substitute 3W +8 for L in the last equation.
    2[(3W+8)+ 2W] = 128
    8W + 16 = 128
    8W = 112
    W = ?
    L = 3W +8 = ?

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  2. L + L + W + W = 128
    L - 8 = 3W
    ================
    Two equations. Two unknowns. Solve simultaneously.

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  3. 3 and 8

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