Calc

Find the points on the graph of y = 1/x where the graph is parallel to the line 4x + 9y = 3.

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asked by Michael
  1. The slope of the straight line
    4x + 9y = 3 is
    -9/4.

    You want points on the line y = 1/x where
    dy/dx = -9/4. Therefore solve
    -1/x^2 = -9/4
    x^2 = 4/9
    x = +2/3 and -2/3.
    At those points, y = 3/2 and -3/2, respectively.
    Therefore there are two points on the curve that satisfy the slope requirement:
    (2/3, 3/2) and (-2/3, -3/2)

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    posted by drwls

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