probabbility

Find the (theoretical) probability of a given event, assuming that the dice are distinguishable and fair, and that what is observed are numbers uppermost.
Two dice are rolled; the numbers add to 7.
1

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asked by LC
  1. Out of 36 possibilities, 7 = 4&3, 3&4, 2&5, 5&2, 6&1 or 1&6. Each has a probability of 1/36.

    To find the "either-or" probability, add the individual probabilities.

    P = 6/36 = 1/6

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    posted by PsyDAG

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