# calculus

what is the area of the region bounded by the curves y=x^2 , y=8-x^2 , 4x-y+12=0

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1. After making a diagram, I cannot tell from the question if you mean the smaller part in quadrant II or the larger part of the region between the two parabolas.

the two parabolas intersect at (2,4) and (-2,4)

and the line intersects the y=x^2 at (-2,4) and (6,36)
and is tangent to the downwards parabola at (-2,4)

I don't see an area bounded by all three.
So the area is zero.

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posted by Reiny

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