# chemistry

what is the pH of an 0.155M aqueous solution of acetic acid if the Ka is 1.8 EE -5?

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1. CH3COOH ==> H^+ + H3COO^-

Ka = (H^+)(CH3COO^-)/(CH3COOH)

(H^+) = x
(CH3COO^-) = x
(CH3COOH) = 0.155-x
Solve for x and convert to pH.

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posted by DrBob222

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