what is the pH of an .200 M aqueous solution of NaOH?
NaOH is a strong base meaning it ionizes 100%; therefore, the (OH^-) is the same as the (NaOH).
pOH = -log(OH^-) = -log(0.200)= ??
pH + pOH = pKw = 14
pOH = -log(OH^-) = -log(0.200)= ??
pH + pOH = pKw = 14