need help figure out how to do these problem:
1)Calculate the pH of this solution: 1.55 X 10^-2 M HBr
2)Determine the pH of this solution: pOH = 8.3
thanks
HBr is a strong acid; i.e., it ionizes 100%. Therefore, the H^+ is the same as the concn of HBr.
pH = -log(H^+) = -log(0.0155)
pH + pOH = pKw = 14