trig

Use the double angle formula to verify the identity cotxsin2x=1+cos2x

  1. 👍 0
  2. 👎 0
  3. 👁 155
asked by SK
  1. ¤©¤·¤¾¤·¤°¤·¤©

    1. 👍 0
    2. 👎 0

Respond to this Question

First Name

Your Response

Similar Questions

  1. advanced functions

    Use the Pythagorean identity to show that the double angle formula for cosine can be written as a) cos2x = 1 - 2sin^2x b) cos2x = 2cos^2x - 1

    asked by Anonymous on November 2, 2009
  2. math

    sin2x-cotx = -cotxcos2x Using the various trigonometric identities(i.e. double angle formulas, power reducing formulas, half angle formulas, quotient identities, etc.) verify the identity. I first added cotx to both sides to get

    asked by sam on April 4, 2008
  3. Trig

    If sinx = 1/4 Find the exact value of cos2x I used the formula for double angle identities : cos2x = 1-2sin^2x and got the answer 1/2 The book says the answer is 7/8 How would they get to that conclusion?

    asked by Don on December 27, 2011
  4. Math

    Use a double-angle formula to find the exact value of cos2x when sinx = 3/5, where pi/2 < x < pi. -(7/25) or 7/25?

    asked by Anonymous on October 30, 2015
  5. Identities

    Verify the following identity cos2x/sin2x+sinx/cosx=csc2x

    asked by Lizzy on November 18, 2015
  6. advanced functions

    Use the Pythagorean Identify to show that the double angle formula for cosine can be written as: cos2x = 2cos^2x - 1

    asked by Anonymous on November 2, 2009
  7. Pre-Cal

    1) Verify the identity cos^2 B - sin^2 B = 2 cos^2 B -1 I know that cos^2 B - sin^2 B = 2 cos^2 B -1 by the double angle formula but I do not know how to show this.

    asked by Hannah on February 27, 2010
  8. trig

    Verify the trigonometric identity: [(1–sin²x)/sin²x]–[(csc²x–1)/cos²x]= -tan²x I can't figure this out.

    asked by Matt on January 23, 2010
  9. trig

    Verify the trigonometric identity: [(1–sin²x)/sin²x]–[(csc²x–1)/cos²x]= -tan²x I still can't figure this out.

    asked by Matt on January 24, 2010
  10. Calculus

    Solve identity, (1-sin2x)/cos2x = cos2x/(1+sin2x) I tried starting from the right side, RS: =(cos²x-sin²x)/(1+2sinxcosx) =(cos²x-(1-cos²x))/(1+2sinxcosx) and the right side just goes in circle. May I get a hint to start off?

    asked by sh on February 27, 2010

More Similar Questions