Chemistry

X rays of wavelength 2.63 were used to analyze a crystal. The angle of first-order diffraction (n = 1 in the Bragg equation) was 16.14°.
What is the spacing between crystal planes?(in pm)

Do I just plug everything in the Bragg's equation?

nλ=d*sinθ
n=1 ?
λ=263 pm?

asked by kay
  1. I remember Bragg's equation being
    n*lambda = 2d*sin theta.

    posted by DrBob222
  2. oh that's right!

    I still have a problem. I'm still getting the wrong answer

    nλ=2d*sinθ
    (1)*(263)/(2*sin(16.14))=d
    -571.8=d

    and the answer is suppose to be 479 pm

    posted by kay
  3. I think you punched in a wrong number somewhere. I get 473 something.

    posted by DrBob222

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