A braking force is applied to a 300-kg motorcycle to reduce its speed from 20.0m/s to 16.0m/s in 10.0s. Find the braking force.
Deceleration:
16 = 20 + Ta
16 - 20 = 10a
a = -0.4 m/s2
Braking force = 300 X 0.4 = -120 N
Please check the above calc and give comments!
To find the braking force applied to the motorcycle, we can use Newton's second law of motion, which states that the force applied to an object is equal to its mass multiplied by its acceleration:
Force = mass × acceleration
In this case, the motorcycle's mass is given as 300 kg. To find the acceleration, we can use the formula:
acceleration = change in velocity / time
The change in velocity is given as 16.0 m/s - 20.0 m/s = -4.0 m/s (negative because the motorcycle is slowing down). The time is given as 10.0 s. Plugging these values into the equation, we get:
acceleration = (-4.0 m/s) / (10.0 s) = -0.4 m/s²
Now, we can plug the values of mass and acceleration into the equation for force:
Force = (300 kg) × (-0.4 m/s²)
Calculating this expression, we find:
Force = -120 N
The negative sign indicates that the force is in the opposite direction of motion, which is the braking force. So, the magnitude of the braking force is 120 N.