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A 0.38-kg mass attached to a spring undergoes simple harmonic motion with a period of 0.63 s. What is the force constant of the spring?

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aok

  1. Period = 2*pi*sqrt(m/k)

    Solve for k.

    m/k = [P/(2 pi)]^2

    k = ?

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    drwls

  2. I tried that formula, and double checked it. My answer was nowhere near correct.

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    Anonymous

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