How many milliliters of a 0.75 M HCL solution do you need to obtain 0.0040 mol of HCL?
This is very like the last one.
0.0040 mol is 4.0 mmoles of HCl
if we need v ml then
v x 0.75 mmoles of HCl
v x 0.75 =4.0
so v= 5.3 ml
(2 sig figs as both 0.75 M and 0.0040 are to 2 sig figs)
Well, well, well. Looks like someone's got a mole situation! To find out how many milliliters of a 0.75 M HCl solution you need, we can use the good ol' formula for molarity: M = moles/volume. Rearranging the formula, we find that volume = moles/M. Plugging in the values, we get volume = 0.0040 mol / 0.75 M. Crunching those numbers, we find that you'd need to obtain approximately 0.00533 liters or 5.33 milliliters of the HCl solution. And just like that, you've got your HCl—no clowning around here!
To calculate the volume of a solution needed to obtain a specific amount of substance, you can use the equation:
moles = concentration (M) x volume (L)
Rearranging the equation, we have:
volume (L) = moles / concentration (M)
Given:
- moles of HCl = 0.0040 mol
- concentration of HCl solution = 0.75 M
Let's substitute these values into the formula to find the volume of the HCl solution:
volume (L) = 0.0040 mol / 0.75 M
volume (L) = 0.0053 L
Since 1 L = 1000 mL, we can convert the volume from liters to milliliters:
volume (mL) = 0.0053 L * 1000 mL/L
volume (mL) = 5.3 mL
Therefore, you would need 5.3 milliliters of a 0.75 M HCl solution to obtain 0.0040 mol of HCl.
To find the volume of a solution we need, we can use the equation:
Molarity (M) = moles (mol) / volume (L)
Rearranging this equation, we get:
Volume (L) = moles (mol) / Molarity (M)
Given that you want to obtain 0.0040 mol of HCl and the molarity of the HCl solution is 0.75 M, we can substitute these values into the equation and solve for volume:
Volume (L) = 0.0040 mol / 0.75 M
Calculating this, we find:
Volume (L) = 0.0053 L
Since the volume unit required is milliliters, we need to convert liters to milliliters by multiplying by 1000:
Volume (mL) = 0.0053 L * 1000 mL/L
Thus, you would need 5.3 mL of a 0.75 M HCl solution to obtain 0.0040 mol of HCl.