How many grams of Au2S can be obtained from 1.17 mol?
g = moles x molar mass
To calculate how many grams of Au2S can be obtained from 1.17 mol, we need to know the molar mass of Au2S.
The molar mass of Au2S (gold(III) sulfide) can be calculated by adding the atomic masses of gold (Au) and sulfur (S).
The atomic mass of gold (Au) is 196.97 g/mol
The atomic mass of sulfur (S) is 32.07 g/mol
So, the molar mass of Au2S is (2 * Au) + S = (2 * 196.97) + 32.07 = 426.01 g/mol.
Now, we can calculate the grams of Au2S obtained from 1.17 mol using the molar mass:
Grams of Au2S = Number of moles * Molar mass
= 1.17 mol * 426.01 g/mol
= 498.16 grams (rounded to two decimal places)
Therefore, approximately 498.16 grams of Au2S can be obtained from 1.17 mol.
To find the number of grams of Au2S that can be obtained from 1.17 mol, you'll need to use the molar mass of Au2S. Here are the steps to calculate it:
1. Determine the molar mass of Au2S. The molar mass is calculated by adding up the atomic masses of each element in the compound.
The atomic mass of gold (Au) is 196.97 g/mol, and the atomic mass of sulfur (S) is 32.07 g/mol. Since there are two Au atoms in Au2S, you multiply the atomic mass of Au by 2.
Molar mass of Au2S = (2 * atomic mass of Au) + atomic mass of S
Molar mass of Au2S = (2 * 196.97 g/mol) + 32.07 g/mol
Molar mass of Au2S = 427.01 g/mol
2. Use the molar mass and the given amount of moles to calculate the grams.
Grams of Au2S = number of moles * molar mass
Grams of Au2S = 1.17 mol * 427.01 g/mol
Grams of Au2S = 499.44 g
Therefore, you can obtain 499.44 grams of Au2S from 1.17 moles.