A young person with normal hearing can hear sounds ranging from 20 Hz to 20 kHz. How many octaves can such a person hear? (Recall that if two tones differ by an octave, the higher frequency is twice the lower frequency)
2x*20 = 20,000
Solve for x = number of octaves. Check my thinking.
210*20 = 20,480 Hz
29*20 = 10,240 Hz
This is my problem:
A proton is propelled east with a speed of 2.1e6 m/s to a region where there is a magnetic field of strength 5 T directed perpendicularly out of the paper. Calculate the radius of the resulting circular trajectory of the proton. A proton has a mass of 1.67e-27 kg and a charge of 1.67e-19 C.
So I am looking for the radius of the loop, right? The formula I have is torque=current*area*strength*sin theta
I need to know torque or the total are to find the radius, right? How do I do that?
To calculate the number of octaves that a person with normal hearing can hear, we need to determine the frequency range covered by 1 octave.
In music theory, an octave is a doubling or halving of a frequency. The frequency ratio between two tones an octave apart is 2:1. Therefore, to find the range of frequencies covered by 1 octave, we divide the upper frequency (20 kHz) by the lower frequency (20 Hz).
20 kHz / 20 Hz = 1000.
This means that there are 1000 frequency intervals (or 1000 octaves) between 20 Hz and 20 kHz.
To determine the number of octaves a person with normal hearing can hear, we first need to understand what an octave is. An octave refers to a musical interval between two frequencies, where the higher frequency is double the lower frequency.
In this case, we have a range of frequencies from 20 Hz to 20 kHz (20,000 Hz). To find the number of octaves within this range, we can divide the highest frequency by the lowest frequency.
Dividing 20,000 Hz by 20 Hz, we get:
20,000 Hz / 20 Hz = 1000
So, a person with normal hearing can hear up to 1000 octaves within the frequency range of 20 Hz to 20 kHz.