Chemistry

If 1.10 g of steam at 100.0 degrees celsius condenses into 38.5 g of water, initially at 27.0 degrees celsius, in an insulated container, what is the final temperature of the entire water sample? Assume no loss of heat into the surroundings

  1. 👍
  2. 👎
  3. 👁
  1. heat lost by 100 C water + heat gained by cold water - heat lost by condensation =0

    1.1*4.184*(Tf-100) +[38.5*4.184*(Tf-27)] - 1.1*2257 = 0
    Solve for Tf.

    You can do it another way if you wish.
    First calculate how much the condensing steam will raise the T of cold water.
    1.1*2257 = 2482.7 J released.
    38.5*4.184*(Tf-27) = 2482.7
    Tf = 42.41 THEN
    heat lost by 1.1g steam @ 100C + heat gained by 41.41 C water = 0 and recalculate Tf EXCEPT, of course, Tinitial is 42.41 and not 27.0 C. Same answer is obtained.

    1. 👍
    2. 👎
  2. Thank you! what is the 2257 from?

    1. 👍
    2. 👎
  3. 2257 is the heat of vaporization of water.

    1. 👍
    2. 👎

Respond to this Question

First Name

Your Response

Similar Questions

  1. Chemistry

    A 100g sample of water at 90 degrees celsius is added to a 100g sample of water at 10 degrees celsius. The final temperature of the water is which of the following: a) between 50 degrees celsius and 90 degrees celsius b) 50

  2. chemistry

    The enthalpy of fusion of ice is 6.020 kJ/mol. The heat capacity of liquid water is 75.4 J/mol degrees Celsius. What is the smallest number of ice cubes at 0 degrees Celsius, each containing one mole of water, necessary to cool

  3. Physics

    How much heat is added to a 10.0 g of ice at -20.0 degrees Celsius to convert it to steam at 120.0 degrees Celsius? compute and add the following heats: heat to heat ice from -20C to 0C heat to melt ice at 0C Heat to heat water

  4. Physics

    Please Help! An object at 20 degrees Celsius with heat capacity 100 calories/Celsius is placed in 40 grams of water at 100 degrees Celsius. After equilibrium is reached, the object is removed from the hot water and placed in 200

  1. physics (please help I have a test tmrw)

    How much thermal energy is released when 500g of steam at 100 degrees C condenses into liquid water and then cools to 50 degrees C? I tried to solve q=mct for q and then use that in the q=mLv formula but it didn't work. The answer

  2. Physics

    How much thermal energy is released when 500 g of steam at 100 degrees celsius condenses into liquid and then cools to 50 degrees celsius. What I`ve Attempted: Q=mLv m = 500g (0.5 kg) Lv = 2.3*10^6 Q=(0.5)(2.3*10^6) Q=1,150,000 J

  3. physics

    An insulated beaker contains 300g of water initially at 30 degree celsius. water at 100 degree celsius is added until the temperature of mixture reaches 50 degree celsius . the specific heat capacity of water is 4.2J/(kg degree

  4. science

    A copper calorimeter weighs 100g when empty, 400g when half full of water at 0 degrees Celsius, and 450g when ice at 0 degree Celsius is added. When some steam is passed into the mixture, its temperature is raised by 10 degrees

  1. physics

    Pls help pls help me solve. Dry steam at 100 degree Celsius is bubbled into 500 g of water originally at 20 degree Celsius. What will be the temperature of the water after 30 g of steam has condensed? ( specific heat capacity of

  2. Physics

    A cube of ice is taken from the freezer at -8.5 degrees celsius and placed in a 100 gram aluminum calorimeter filled with 300 grams of water at room temperature of 20 degrees celsius. the final situation is observed to be all

  3. Chemistry

    What will be the final temperature of the water in an insulated container as the result of passing 6.00g of steam at 100.0 degrees Celsius into 100.0g of water at 24.0 degrees Celsius?

  4. chemistry

    How much heat is necessary to change a 52.0 g sample of water at 33 degrees celsius into steam at 110 degrees celsius?

You can view more similar questions or ask a new question.