# Precalculus

1. Write the given expression as a single logarithm.
log(70x)+log(10y)-2

2. Write the given expression as a single logarithm.
ln7e/(square root 2x)-ln(square root 2ex)

3. Write the given expression as a single logarithm.
-2Ln(x)+Ln(4y)-Ln(5z)

1. 1. log (70x/(10y)) - 2
= log (7x/y) - 2

2. not clear if the √(2x) is part of the first ln or not.

3. -2lnx + ln(4y) - ln(5z)
= ln [ (x^2)(4y)/(5z) ]

posted by Reiny

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