A swimming pool 16.0 m by 9.1 m and uniform depth is 2.0 m. What will be the pressure against the side of the pool near the bottom?
To find the pressure against the side of the pool near the bottom, we can use the concept of pressure in fluid mechanics. The pressure exerted by a fluid at a particular depth is given by the formula:
Pressure = density * gravitational acceleration * height
In this case, we know that the pool has a uniform depth of 2.0 m. We also need to know the density of the fluid. Let's assume that the pool is filled with water, which has a density of approximately 1000 kg/m^3. Finally, we need to know the gravitational acceleration, which is approximately 9.8 m/s^2.
Using these values, we can calculate the pressure exerted by the water against the side of the pool near the bottom.
Pressure = density * gravitational acceleration * height
= 1000 kg/m^3 * 9.8 m/s^2 * 2.0 m
= 19600 N/m^2 (Pascals)
Therefore, the pressure against the side of the pool near the bottom is 19600 Pascals.