A chemist wants to make 4.5 L of a 0.310 M CaCl2 solution what mass of CaCl2 (in g) should the chemist use

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  1. How many moles do you want?
    moles = M x L = ??
    Then moles = grams/molar mass
    Solve for grams.

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  2. .310*4.5*82.96

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  3. 115.7

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