What force is required to accelerate a 90kg bike to 20 m/s in 15 sec?
I need to know HOW to do it!
first, recall formula for Force:
F = ma
where m = mass in kg, and a = acceleration in m/(s^2)
then also recall the formula for acceleration,,
acceleration is change in velocity over time, thus:
a = (v - v0)/t
where v = final velocity in m/s
v0 = initial velocity in m/s
t = time in s
since you are you are given velocity and time, calculate for a first,, assuming the bike is initially at rest, v0 = 0:
a = (v - v0)/t
a = 20/15 = ? *solve this*
after that, substitute this to
F = ma
since you are also given the mass, you can solve for F.
hope this helps.
thanks
To calculate the force required to accelerate the bike, we need to use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
In this case, the mass of the bike is given as 90 kg and the desired acceleration is not given directly, but we can calculate it using the given final velocity and time.
Acceleration (a) can be calculated using the formula:
a = (final velocity - initial velocity) / time
Given that the initial velocity of the bike is 0 m/s (assuming it starts from rest), the acceleration can be calculated as:
a = (20 m/s - 0 m/s) / 15 s
Which simplifies to:
a = 20 m/s / 15 s
Now that we have the acceleration, we can use Newton's second law to find the force:
F = m * a
Plugging in the values we have:
F = 90 kg * (20 m/s / 15 s)
Simplifying the equation gives:
F = 6 N
Therefore, the force required to accelerate the 90 kg bike to a velocity of 20 m/s in 15 seconds is 6 Newtons.