Each increase in pressure of 100 atm decreases the melting point of water by 1.0 degrees C.
Estimate the temperature at which liquid water freezes under a pressure of 400 atm.
How do I approach this problem?
You can be VERY simple with it like this:
100 atm = -1.0 C
200 atm = -2.0 C.
300 atm = -3.0 C.
400 atm = -4.0 C.
OR you can do it all at one time.
-1.0 c x (400 atm/100 atm) = -4.0 C
To approach this problem, you can use the given information that each increase in pressure of 100 atm decreases the melting point of water by 1.0 degrees Celsius.
Start by calculating the change in pressure from the given 400 atm to the normal pressure of 1 atm. Subtract the normal pressure from the given pressure: 400 atm - 1 atm = 399 atm.
Next, divide the change in pressure by 100 atm per degree Celsius to find the change in temperature in degrees Celsius: 399 atm / 100 atm/°C = 3.99 °C.
Finally, subtract the calculated change in temperature from the freezing point of water under normal pressure, which is 0 °C: 0 °C - 3.99 °C = -3.99 °C.
Therefore, under a pressure of 400 atm, liquid water would freeze at an estimated temperature of approximately -3.99 °C.