An object traveling 200 feet per second slows to 50 feet per second in 5 seconds. Calculate the acceleration of the object.
hi !! :)
transport topic ? i just did that and it wasn't my strongest but i'll give it a shot :) hope i help but sorry if its way out lol !! :)
a = v-u/t
a=x
v (final speed) = 50 feet/second
u (initial speed) = 200 feet/second
t = 5 seconds
a=50-200
=-150/5
=-30
or you could use the equation:
change in speed/time taken for change
sorry but maybe one of these ring a bell i'm not 100% sure ? :S and also we use metres per second so when you are doing it if that's what you usually use then you should probably convert it ?
eg. 200 feet = 60.96 metres
then acceleration would be in metres per second squared m/s^2 or ms^-2
To calculate the acceleration of the object, you can use the formula:
acceleration (a) = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 200 feet per second
Final velocity (v) = 50 feet per second
Time (t) = 5 seconds
Substituting these values into the formula:
acceleration (a) = (50 - 200) / 5
Simplifying this expression:
acceleration (a) = -150 / 5
Dividing -150 by 5:
acceleration (a) = -30 feet per second squared
Thus, the acceleration of the object is -30 ft/s². The negative sign indicates that the object is decelerating or slowing down.
The definition of acceleration will tell you what to do.
Velocity change divided by time interval