the chippa soccer association calculates its profit from gate taking match according to this formular
p=5n-55
Where p is profit in rand an n is the number of people in the stadium
a.calculate the profit when the number of people in the stadium is 250
b.if n=10,find p.explain what this means
c.after a pariticular match the profit gained by the association was R600
How many people watch the match that day
d.how many people must attend the match so that the association does not make a loss
a. Just plug in the n value into your formula and solve for p.
b. Plug in again, what do you think it means?
c. Plug in 600 for p and solve for n
d. Assuming 55 is the cost, 5n ≥ 55.
PROFIT AND LOSS
a. To calculate the profit when the number of people in the stadium is 250, you can use the given formula:
p = 5n - 55
Let's plug in the value of n as 250:
p = 5(250) - 55 = 1250 - 55 = 1195
Therefore, when the number of people in the stadium is 250, the profit is R1195.
b. If n = 10, you need to find the value of p. Using the same formula:
p = 5n - 55
Plug in the value of n as 10:
p = 5(10) - 55 = 50 - 55 = -5
When n = 10, the profit (p) is -5. This means that the association is making a loss of R5.
c. If the profit gained by the association was R600, we can use the formula to find the number of people who watched the match:
p = 5n - 55
Since the profit gained was R600, we know that p = 600. We can rearrange the formula to solve for n:
600 = 5n - 55
Add 55 to both sides:
655 = 5n
Divide both sides by 5:
n = 655/5 = 131
Therefore, 131 people watched the match that day.
d. To find the number of people that must attend the match so that the association does not make a loss, we can set the profit formula equal to zero:
p = 5n - 55
0 = 5n - 55
Add 55 to both sides:
55 = 5n
Divide both sides by 5:
n = 55/5 = 11
So, the association must have at least 11 people attend the match in order to break even and not make a loss.