Posted by JoniAnne on Wednesday, October 20, 2010 at 11:50am.
Please check-
Solve 3 > sqrt(3x)
3x >=o
x>=o/3
x>=0
square both sides and you have 3x < 3^2
3x,9
x<9/3
x<3
answer is 0<=x<3 correct or not?
3(cube) sqrt(2-5) = 3
cube both sides = 2-5x = 27
-5x = 25
x = -5, correct?
Thank you