the membership fee for oining a camp association is 45 a local campground charges members of the camping associatons 35 per night for a campsite and non members 40 per night, after how many nights of camping is the total cost for the members includingthe membership fee, the same as the total cost for the non members?

I know that your supposed to make a table for this or something, but I have no idea what to include in the table, can somebody help me make the table?

number of nights ---- n

solve
40n = 35n + 35

Sure, I can help you make a table to solve this problem.

To solve this problem, we need to determine the number of nights of camping where the cost for members and non-members is equal. Let's start by creating a table to organize the information:

| Nights of Camping | Cost for Members | Cost for Non-Members |
|-------------------|-----------------|---------------------|

We will fill in this table step by step. But first, let's define some variables to help us with the calculations:

Let M represent the total cost for members (including the membership fee).
Let N represent the total cost for non-members.

Now, as given in the problem:

The membership fee for joining the campground association is $45.
The cost for members for a campsite per night is $35.
The cost for non-members for a campsite per night is $40.

To calculate M and N, we can use the following formulas:

M = Membership Fee + (Cost per night for members x Number of nights)
N = Cost per night for non-members x Number of nights

Now let's fill in the table for different numbers of nights:

| Nights of Camping | Cost for Members | Cost for Non-Members |
|-------------------|------------------------------|------------------------------|
| 1 | $45 + (35 x 1) = $80 | $40 x 1 = $40 |
| 2 | $45 + (35 x 2) = $115 | $40 x 2 = $80 |
| 3 | $45 + (35 x 3) = $150 | $40 x 3 = $120 |
| 4 | $45 + (35 x 4) = $185 | $40 x 4 = $160 |
| 5 | $45 + (35 x 5) = $220 | $40 x 5 = $200 |
| ... | ... | ... |

You can continue filling in the table with different numbers of nights until you find the number of nights where the total cost for members and non-members is equal. In this case, you need to find the row where the Cost for Members is equal to the Cost for Non-Members.

Alternatively, you can use algebra to solve for the number of nights. Let's set M = N and solve for the number of nights:

$45 + (35 x n) = $40 x n

Now you can solve this equation for n to find the number of nights where the total cost for members and non-members is equal.