Draw an orbital diagram showing valence electrons and write the condensed ground-state electron configuration for Se3+
To draw the orbital diagram, we first need to determine the number of valence electrons in Se3+.
A neutral selenium (Se) atom has an atomic number of 34, which means it has 34 electrons. The 3+ charge indicates that the atom has lost 3 electrons.
To determine the number of valence electrons, we need to consider the electron configuration of a neutral selenium atom:
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^4.
The valence electrons are those in the outermost shell, which is the 4th shell (n=4). The 4s^2 and 4p^4 electrons are the valence electrons, so there are a total of 6 valence electrons.
Now, let's draw the orbital diagram for Se3+:
1s [X]
2s [X]
2p [X] [X] [X] [X]
3s [X] [X]
3p [X] [X] [X] [X] [X] [X]
4s
3d
4p
The X's represent the electrons.
In the orbital diagram, we fill in the orbitals with the valence electrons in a specific order: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p.
For Se3+, we start by removing the 3 electrons from the 4p orbital. This leaves us with only 3p, 4s, 3d orbitals remaining.
The electrons are filled as follows:
1s [ ]
2s [ ]
2p [ ] [ ] [ ] [ ]
3s [ ] [ ]
3p [ ] [ ] [ ] [ ] [ ] [ ]
4s
3d
4p
Now, we need to fill in the remaining 6 electrons in the 3p, 4s, and 3d orbitals.
1s [ ]
2s [ ]
2p [ ] [ ] [ ] [ ]
3s [ ] [ ]
3p [X] [X] [X] [X] [X] [X]
4s [X] [X]
3d [ ]
The resulting orbital diagram for Se3+ shows that it has 6 valence electrons, represented by the X's in the 3p orbital.
The condensed ground-state electron configuration for Se3+ is [Ar] 3d^10 4s^2 3p^6. The [Ar] represents the electron configuration of argon (which contains 18 electrons) before the 4s, 3d, and 3p orbitals.
Hope this helps!
To draw the orbital diagram for Se3+, we need to determine the number of valence electrons first.
Selenium (Se) has an atomic number of 34, which means it has the electron configuration 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁴.
To find the number of valence electrons, we need to look at the outermost energy level, which is the fourth energy level (4s² 4p⁴). In this case, we have 2 electrons in the 4s orbital and 4 electrons in the 4p orbital, totaling 6 valence electrons.
Now, let's draw the orbital diagram:
1s ↑↓
2s ↑↓
2p ↑↓ ↑↓ ↑
3s ↑↓
3p ↑↓ ↑↓ ↑
4s ↑↓
3d ↑↓ ↑↓ ↑↓ ↑↓ ↑
4p ↑↓ ↑↓ ↑↓ ↑
In the orbital diagram, each orbital is represented by a box, and the arrows indicate the electrons. The arrows pointing up (↑) represent electrons with a positive spin (+1/2), while the arrows pointing down (↓) represent electrons with a negative spin (-1/2).
Finally, let's write the condensed ground-state electron configuration for Se3+ by removing the outermost 3 electrons from neutral Se:
1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰.
Note that since Se3+ has lost 3 electrons, the electron configuration will be missing the 4s² 4p⁴ part.