How many moles of O2 are needed to react with 2.90 moles C2H2
To determine the number of moles of O2 needed to react with 2.90 moles of C2H2, we first need to balance the equation for the reaction between C2H2 (acetylene) and O2 (oxygen). The balanced equation is:
2 C2H2 + 5 O2 → 4 CO2 + 2 H2O
From the balanced equation, we can see that the stoichiometric ratio between C2H2 and O2 is 2:5. This means that for every 2 moles of C2H2, 5 moles of O2 are needed.
Now, given that we have 2.90 moles of C2H2, we can use this stoichiometric ratio to calculate the number of moles of O2 needed.
(2.90 moles C2H2) x (5 moles O2 / 2 moles C2H2) = 7.25 moles O2
Therefore, 7.25 moles of O2 are needed to react with 2.90 moles of C2H2.
To determine the number of moles of O2 needed to react with 2.90 moles of C2H2, we will use the balanced chemical equation for the reaction between O2 and C2H2.
The balanced chemical equation is:
2 C2H2 + 5 O2 -> 4 CO2 + 2 H2O
According to the equation, it takes 5 moles of O2 to react with 2 moles of C2H2.
Therefore, to find out how many moles of O2 are needed to react with 2.90 moles of C2H2, we can set up a proportion:
5 moles O2 / 2 moles C2H2 = x moles O2 / 2.90 moles C2H2
Solving for x:
x moles O2 = (5 moles O2 / 2 moles C2H2) * 2.90 moles C2H2
x = (5/2) * 2.90
x = 7.25
Therefore, 7.25 moles of O2 are needed to react with 2.90 moles of C2H2.