inverse trig functions
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Intergrate ¡ì sec^3(x) dx could anybody please check this answer. are the steps correct? thanks. = ¡ì sec x d tan x = sec x tan x  ¡ì tan x d sec x = sec x tan x  ¡ì sec x tan^2(x) dx = sec x tan x + ¡ì sec x dx  ¡ì
asked by Vidal on October 15, 2006 
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if you can't help me with my first question hopw you can help me with this one. sec(x)/csc(x)=tan(x) thanx to anyone who can help From the definition of the sec and csc functions, and the tan function, sec(x)/csc(x) =
asked by berhana on November 6, 2006 
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Reduce (csc^2 x  sec^2 X) to an expression containing only tan x. (is this correct?) csc x = 1/sin x sec x = 1/cos x tan x = 1/cot x sin^2 x + cos^2 x = 1 1 + cot^2 x = csc^2 x tan^2 x + 1 = sec^2 x csc^2 x  sec^2 x = 1 + cot^2
asked by Anonymous on February 1, 2011 
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Verify the following: 1. cos x/(1sinx)= sec x + tan x 2. (tanx+1)^2=sec^2x + 2tan x 3. csc x = )cot x + tan x)/sec x 4. sin2x  cot x = cotxcos2x
asked by Trevor on October 13, 2009 
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asked by Girly Girl on March 21, 2018 
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Given that sec 3π/10 ≈ 17/10 and csc 3π/10 ≈ 17/14, find the following: 1. sin 3π/10 ≈ 14/17 (is this one correct) 2. csc 43π/10 ≈ 3. sec 2π/10 ≈ 4. cot 12π/10 ≈ 5. tan π/5 ≈ 6. sin 7π/10 ≈ 7. cos 13π/10
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I'm trying to verify these trigonometric identities. 1. 1 / [sec(x) * tan(x)] = csc(x)  sin(x) 2. csc(x)  sin(x) = cos(x) * cot(x) 3. 1/tan(x) + 1/cot(x) = tan(x) + cot(x) 4. csc(x)/sec(x) = cot(x)
asked by Liath on September 21, 2009 
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I am having trouble with this problem. sec^2(pi/2x)1= cot ^2x I got : By cofunction identity sec(90 degrees  x) = csc x secx csc1 = cot^2x Then split sec x and csc1 into two fractions and multiplied both numerator and
asked by Hutch on March 9, 2015 
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What is a simplified form of the expression sec^2x1/sin x sec x ? a)cot x b)csc x c)tan x d)sec x tan x Please help me :(
asked by Unknown on May 27, 2018 
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Julia wants to simplify the term sec^2 theta1/cot^2 theta+1 in a trigonometric identity that she is proving. Which of the following identities should use to help her? Select all that apply. (2 ANSWERS) a. sin^2 theta+cos^2
asked by girly girl on April 23, 2018