how do i solve x^4-13^2+40?
i think ur question is wrong but i solved it nd got x^4-129
Since it is not an equation, it cannot be "solved."
However, 13^2 = 169
x^4 - 169 + 40 = x^4 - 129
To solve the expression x^4 - 13x^2 + 40, you can follow these steps:
Step 1: Rewrite the expression as a quadratic equation.
Let's replace the x^4 term with a variable, say, y. The expression becomes y - 13x^2 + 40.
Step 2: Solve the quadratic equation.
Now, we have a quadratic equation in terms of y:
y - 13x^2 + 40 = 0
To solve this equation, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
For our equation, a = 1 (coefficient of y), b = -13 (coefficient of x^2), and c = 40. Plugging these values in, we get:
x = (-(-13) ± √((-13)^2 - 4(1)(40))) / (2(1))
= (13 ± √(169 - 160)) / 2
= (13 ± √9) / 2
= (13 ± 3) / 2
We obtain two solutions for x:
x1 = (13 + 3) / 2 = 16/2 = 8
x2 = (13 - 3) / 2 = 10/2 = 5
Therefore, the solutions to the equation x^4 - 13x^2 + 40 = 0 are x = 8 and x = 5.