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f(t) = t2 − 1

Find the equation of the line tangent to the graph of f(t) at t = 5.
Enter the equation of the tangent line here (in terms of the variable t):
y =

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  1. I am sure you meant
    f(t) = t^2 - 1
    f '(t) = 2t

    when t = 5
    f(5) = 24
    so we have the contact point (5,24)
    f '(5) = 10
    so the slope of the line is 10

    finish it by using the method you learned to find the equation of a line, given the slope and a point

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