how many moles of ions are released when 1.6 mol of ammonium phosphate is dissolved in water?
Well, ammonium phosphate, (NH4)3PO4, has a total of 4 ions present when it dissociates in water. So, when you dissolve 1.6 moles of ammonium phosphate, you would release 1.6 moles multiplied by 4, which is... enough moles to form a very noble-ion party!
To determine the number of moles of ions released when 1.6 mol of ammonium phosphate is dissolved in water, we need to consider the dissociation of ammonium phosphate.
Ammonium phosphate (NH4)3PO4 consists of 3 ammonium ions (NH4+) and 1 phosphate ion (PO43-).
When (NH4)3PO4 dissolves in water, it dissociates into its constituent ions:
(NH4)3PO4 → 3 NH4+ + PO43-
From the balanced equation, we can see that one mole of (NH4)3PO4 produces 3 moles of NH4+ ions and 1 mole of PO43- ion.
Therefore, if we have 1.6 moles of (NH4)3PO4, it will produce:
1.6 moles x 3 moles = 4.8 moles of NH4+ ions
1.6 moles x 1 mole = 1.6 moles of PO43- ion
Therefore, when 1.6 mol of ammonium phosphate is dissolved in water, it releases 4.8 moles of NH4+ ions and 1.6 moles of PO43- ion.
To determine the number of moles of ions released when 1.6 mol of ammonium phosphate (NH4)3PO4 is dissolved in water, you need to first understand the chemical formula and properties of ammonium phosphate.
The formula for ammonium phosphate, (NH4)3PO4, tells us that each molecule of ammonium phosphate releases 3 ammonium ions (NH4+) and 1 phosphate ion (PO43-) when it dissolves in water.
Since there are 3 ammonium ions released per molecule of ammonium phosphate, the number of moles of ammonium ions can be calculated by multiplying the number of moles of ammonium phosphate by 3:
Number of moles of ammonium ions = 1.6 mol (NH4)3PO4 * 3 mol NH4+/1 mol (NH4)3PO4 = 4.8 mol NH4+
Similarly, as there is 1 phosphate ion released per molecule of ammonium phosphate, the number of moles of phosphate ions can be calculated by multiplying the number of moles of ammonium phosphate by 1:
Number of moles of phosphate ions = 1.6 mol (NH4)3PO4 * 1 mol PO43-/1 mol (NH4)3PO4 = 1.6 mol PO43-
Therefore, when 1.6 mol of ammonium phosphate is dissolved in water, it releases 4.8 moles of ammonium ions (NH4+) and 1.6 moles of phosphate ions (PO43-).
1.6 moles (NH3)3PO4 will give you
1.6 moles of PO4^-3 ions and 3 x 1.6 = 4.8 moles NH4^+ ions. The total is 1.6 + 4.8 = ??