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A hydrate of zinc nitrate has the formula Zn(NO3)2 . xH2O. If the mass of 1 mol of anhydrous zinc nitrate is 63.67% of the mass of 1 mol of the hydrate, what is the value of x?

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Marty

  1. So the %H2O = 100 - 63.67 = 36.33
    a 100 g sample contains 64.67 g Zn(NO3)2 and 36.33 g H2O.
    mols H2O = 36.33/18.015
    mols Zn(NO3)2 = 63.67/molar mass zinc nitrate (don't include the water).
    Find the ratio of mols H2O to 1 mol Zn(NO3)2. That will be x in the formula.

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    DrBob222

  2. 7.8

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    hamna

  4. x=6

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    Joe

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