The Cu2+ ions in this experiment are produced by the reaction of 1.0 g copper turnings with excess nitric acid. How many moles of Cu2+ are produced?
moles Cu = 1g/atomic mass Cu = ??
first do gram to mole conversion
63.5g one atom of Cu...1g of Cu x 1 mole of Cu/63.5 gram of Cu = 1.6x10^-2moles cu.
1 to 1 ration, therefore, 1.6x10^-2 moles
Well, let me calculate that for you.
First, we need to find the molar mass of copper (Cu), which is approximately 63.55 g/mol.
Next, we convert the mass of copper turnings from grams to moles using the molar mass:
1.0 g Cu / 63.55 g/mol Cu ≈ 0.0157 mol Cu
Since the reaction produces 1 mol of Cu2+ ions per mole of Cu, we can say that:
0.0157 mol Cu = 0.0157 mol Cu2+
Therefore, approximately 0.0157 moles of Cu2+ ions are produced.
To find the number of moles of Cu2+ produced, we need to use the given mass of copper turnings, the molar mass of copper (Cu), and the balanced chemical equation for the reaction.
First, let's determine the molar mass of copper (Cu). The molar mass of an element is its atomic mass expressed in grams per mole. The atomic mass of copper is approximately 63.55 g/mol.
Next, we can calculate the number of moles of copper (Cu) using the mass of copper turnings given in the question. The mass of copper turnings is given as 1.0 g.
Moles of Cu = (Mass of Cu) / (Molar mass of Cu)
Moles of Cu = 1.0 g / 63.55 g/mol
Now, we need to determine the stoichiometry of the balanced chemical equation for the reaction between copper turnings and nitric acid to find the number of moles of Cu2+ produced.
The balanced chemical equation for the reaction can be written as:
Cu + 4HNO3 -> Cu(NO3)2 + 2NO2 + 2H2O
From the balanced equation, we can deduce that for every 1 mole of copper (Cu) reacted, 1 mole of Cu2+ is produced. Therefore, the number of moles of Cu2+ produced is equal to the number of moles of Cu.
Moles of Cu2+ produced = Moles of Cu
Moles of Cu2+ produced = 1.0 g / 63.55 g/mol
Now, we can substitute the given values into the equation to calculate the number of moles of Cu2+ produced.
Moles of Cu2+ produced = 1.0 g / 63.55 g/mol
Moles of Cu2+ produced ≈ 0.0157 mol
Therefore, approximately 0.0157 moles of Cu2+ are produced in the experiment.