Consider the circuit shown in the figure below. Use the following as necessary: R1 = 11.00 Ù, R2 = 1.40 Ù, and V = 6.00 V.

(a) Calculate the equivalent resistance of the R1 and 5.00 Ù resistors connected in parallel.
1 Ù

(b) Using the result of part (a), calculate the combined resistance of the R1, 5.00 Ù, and 4.00 Ù resistors.
2 Ù

(c) Calculate the equivalent resistance of the combined resistance found in part (b) and the parallel 3.00 Ù resistor.
3 Ù

(d) Combine the equivalent resistance found in part (c) with the R2 resistor.
4 Ù

(e) Calculate the total current in the circuit.
5 A

(f) What is the voltage drop across the R2 resistor?
6 V

(g) Subtracting the result of part (f) from the battery voltage, find the voltage across the 3.00 Ù resistor.
7 V

(h) Calculate the current in the 3.00 Ù resistor.
8 A

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asked by chuck
  1. Sorry, without the accompanying figure, it is quite difficult to guess what the circuit is like.
    See if you can post a link, although it is not always possible.

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    posted by MathMate

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