if a motorcycle accelerates from rest through the 400 m in 10 sec flat. What is its acceleration?
a = (deltav)/t
= (d/t)/t
=(400/10) / 10
=4m/s
:)
Both the numerical value and the dimensions of Rose's answer are wrong.
d/t (in her answer) is the average velocity, not the final velocity or deltav.
Although we do welcome the help of others, be skeptical of answers not posted by Jiskha staff
(1/2) a t^2 = 400 m
a = 2*400 m*/(10s)^2 = 8 m/s^2
acceleration=v-u/t
=400-0/10
=400/10
=40m/sec
To find the acceleration of the motorcycle, we can use the equation:
acceleration = (final velocity - initial velocity) / time
In this case, the motorcycle starts from rest, so its initial velocity is 0 m/s. The distance traveled is 400 m, and the time taken is 10 seconds.
First, let's calculate the final velocity of the motorcycle. We can use the formula:
final velocity = distance / time
final velocity = 400 m / 10 s = 40 m/s
Now, we can substitute the values into the acceleration formula:
acceleration = (40 m/s - 0 m/s) / 10 s = 4 m/s²
Therefore, the acceleration of the motorcycle is 4 m/s².