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Suppose that the heights of adult men in the United States are normally distributed with a mean of inches and a standard deviation of inches. What proportion of the adult men in United States are more than feet tall? (Hint: feet inches.) Round your answer to at least four decimal places.

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Anonymous

  1. find the z-score:
    z=(x-mu)/sigma
    where mu= mean and sigma=standard deviation

    after you find the z-score, you need to look at the z-score chart for the proportion
    http://www.thebeststatistics.info/sta/table_zvals.html

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    TutorCat

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