If 4.50 g of (NH4)2SO4 is dissolved in enough water to form 250. mL of solution, what is the molarity of the solution?
mols = 4.50 g/molar mass
molarity = moles/L of solution.
0.12M
To find the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters).
1. First, determine the number of moles of (NH4)2SO4. To do this, you need to know the molar mass of (NH4)2SO4.
(NH4)2SO4 has the following atomic masses:
N: 14.01 g/mol
H: 1.01 g/mol
S: 32.06 g/mol
O: 16.00 g/mol
Calculate the molar mass:
(2 * N) + (8 * H) + S + (4 * O) = 132.14 g/mol
2. Convert the mass of (NH4)2SO4 to moles:
moles = mass / molar mass
moles = 4.50 g / 132.14 g/mol
3. Now, convert the volume of the solution to liters:
250 mL = 250/1000 = 0.250 L
4. Finally, calculate the molarity using the formula:
Molarity (M) = moles of solute / volume of solution (L)
Molarity = moles / volume
Plug in the values:
Molarity = (4.50 g / 132.14 g/mol) / 0.250 L
Calculate the molarity to get the final answer.