Silver has two naturally occurring isotopes (Ag-107 and Ag-109).
(a) Use the periodic table to find the atomic mass of silver.
(b) If the natural abundance of Ag-107 is 51.84%, what is the natural abundance of Ag-109?
(c) If the mass of Ag-107 is 106.905, what is the mass of Ag-109?
a). Look it up on the periodic table.
b). If the total is 100 and one is 51.84, wouldn't the other one be 100-51.84?
c). mass107*fraction + mass109*fraction = atomic mass Ag.
Post your work if you get stuck.
(a) To find the atomic mass of silver, you can refer to the periodic table. The atomic mass is usually listed below the element symbol. In this case, you would look up the element symbol for silver (Ag) on the periodic table and find the atomic mass.
(b) The natural abundance of Ag-107 is given as 51.84%. The total natural abundance of both isotopes must add up to 100%. Since there are only two isotopes of silver, the natural abundance of Ag-109 can be calculated by subtracting the natural abundance of Ag-107 from 100%.
Natural abundance of Ag-109 = 100% - 51.84% = 48.16%
(c) The mass of Ag-107 is given as 106.905. To find the mass of Ag-109, you need to subtract the mass of Ag-107 from the atomic mass of silver.
Mass of Ag-109 = Atomic mass of silver - Mass of Ag-107
Mass of Ag-109 = Atomic mass of silver - 106.905
(a) To find the atomic mass of silver (Ag), we need to calculate the weighted average mass of its isotopes, taking into account their natural abundances. We can find the atomic masses of Ag-107 and Ag-109 on the periodic table, which are respectively 106.905 amu and 108.905 amu.
(b) Let x be the natural abundance of Ag-109. Since the sum of the natural abundances of both isotopes is 100%, we can write the equation:
51.84% + x% = 100%
Solving for x, we get:
x% = 100% - 51.84% = 48.16%
Therefore, the natural abundance of Ag-109 is 48.16%.
(c) We are given the mass of Ag-107, which is 106.905 amu. To find the mass of Ag-109, we subtract the mass of Ag-107 from the atomic mass of Ag-109:
Mass of Ag-109 = Atomic mass of Ag-109 - Mass of Ag-107
= 108.905 amu - 106.905 amu
= 2.00 amu
Therefore, the mass of Ag-109 is 2.00 amu.