# Math clarification Reiny

This is the problem you helped me with. I was curious, do I write the solution set as (1 + i3�ã3)/2,
(1-i3�ã3)/2

change it to the standard form first

x^2 - x + 7 = 0
a=1, b=-1, c = 7

x = (1 �} �ã(1 - 4(1)(7))/2
= (1 �} �ã-27)/2

Your answer is an imaginary number or called a complex number, you could rewrite is as
x = (1 �} 3�ã3 i)/2

1. 2

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This is the problem you helped me with. I was curious, do I write the solution set as (1 + i3ã3)/2, (1-i3ã3)/2 change it to the standard form first x^2 - x + 7 = 0 a=1, b=-1, c = 7 x = (1 } ã(1 - 4(1)(7))/2 = (1 }
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