Math HELP!

I posted a few questions and then went back and posted how I thought they were supposed to be answered. Could someone please locate my earlier questions and tell me if I am on the right track?

asked by Sabrina
  1. I answered some of them

    click on your name above and you will see your posts

    posted by Reiny
  2. Thank you Reiny so much for you help. Can you tell me if I am on the right track with this problem: 4c^2/4c^2-8c+4 x 4c-4/2c When solving this am I supposed to find the gcf or lcm to solve> would the lcm be 2 and the gcf be 16? I don't know if I am even going down the right road here?

    posted by Sabrina
  3. Use brackets to show when the denominator ends
    I think you meant
    4c^2/(4c^2-8c+4)( 4c-4)/2c , which is
    = 4c^2/(4(c^2 - 2c + 1)(4)(c-1)/(2c)
    = 4c^2/(4(c- 1)^2(4)(c-1)/(2c)

    now things cancel rather nicely

    final result

    2c/(c-1) , c ≠ 1,0

    posted by Reiny
  4. THANKS!!!!!! Just one question, when I follow these steps and get to the result is it both 2c/(c-1), c‚ 10 or am I reading my problem wrong and the answer is just c‚ 10

    posted by Sabrina
  5. The final answer is
    2c/(c-1)

    the part after it is the restriction.
    you are reading it wrong, it does not have 10 in it.
    it says, c cannot be equal to 1 or c cannot be equal to 0
    Since we cannot divide by zero, those values would make the denominators we canceled equal to zero.

    posted by Reiny

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