if 8.00kJ of heat added to 200. g of water at 20.0 C what is final temperature of water?
q = mass water x specific heat water x (Tfinal-Tinitial).
Substitute and solv for Tfinal.
To determine the final temperature of the water after adding 8.00 kJ of heat, you can use the equation:
q = m * C * ΔT
Where:
q = amount of heat transferred (in Joules)
m = mass of the water (in grams)
C = specific heat capacity of water (4.18 J/g·°C)
ΔT = change in temperature (final temperature - initial temperature)
First, convert the mass from grams to kilograms:
200 g = 0.2 kg
Next, calculate the amount of heat transferred:
q = 8000 J (since 1 kJ = 1000 J)
Now, we can rearrange the equation to solve for ΔT:
ΔT = q / (m * C)
Substituting the values:
ΔT = 8000 J / (0.2 kg * 4.18 J/g·°C)
ΔT ≈ 959.81 °C
To find the final temperature, add the change in temperature to the initial temperature:
Final temperature = Initial temperature + ΔT
Substituting the values:
Final temperature ≈ 20 °C + 959.81 °C
Final temperature ≈ 979.81 °C