Chemistry

The heat of fusion of water is 6.01 kJ/mol. The heat capacity of liquid water is 75.3 J/mol • K. The conversion of 50.0 g of ice at 0.00°C to liquid water at 22.0°C requires how much kJ of heat?
Can someone explain how to do this, I tried but keep getting the wrong answer.

asked by Anonymous
  1. 50/18.015 = moles in 50 g H2O.

    q1 = heat to melt ice.
    q1 = moles H2O x 6.01 kJ/mol

    q2 = heat to move ice water from zero C to 22 C.
    q2 = moles water x 75.3 J/mole x (22-0).
    Change q1 to J and add to q2.

    posted by DrBob222
  2. 10.6kj

    posted by maria

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