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Find an equation of the tangent line to the curve at the given point.
y = 6 x sin x
P= (pi/2 , 3pi)

i know the slope of a tangent line is equal to the first derivative. For that I got 6xcosx + 6sinx but idk how to put that into the y-y1=m(x-x1) formula to make the equation

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calc

  1. great job on the first derivative!

    m=slope
    m= 6(pi/2)cos(pi/2) + 6sin(pi/2)

    y1=3pi
    x1=pi/2

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  2. oh! ok! thank you!
    so then m=6 and the equation of the tangent line would be y=6x
    Thank you!

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    calc

  4. remember to plug in your y1 and x1 & solve for y!

    y-y1=m(x-x1)
    y-3pi=6(x-pi/2)

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