Calculate the pressure exerted by 1.0 mol C2H6 behaving as a perfect gas
At STP, a perfect gas occupies 22.4 L. per mole. Use PV = nRT.
To calculate the pressure exerted by a gas, you can use the ideal gas law equation, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
In this case, we are given that 1.0 mol of C2H6 is behaving as a perfect gas. To calculate the pressure, we need to know the volume, temperature, and the gas constant.
The volume and temperature will vary depending on the specific conditions of the gas. If these are not provided, you will need additional information to calculate the pressure. The gas constant, denoted by R, is a universal constant and has a value of 0.0821 L·atm/(mol·K) or 8.314 J/(mol·K).
Once you have the values for volume (V), temperature (T), and gas constant (R), you can rearrange the ideal gas law equation to solve for pressure (P). The equation becomes P = (nRT) / V.
Plug in the given values into the equation, and you will be able to calculate the pressure exerted by 1.0 mol of C2H6 behaving as a perfect gas.