A flask has a mass of 78.23 g when empty and 593.63 g when filled with water. When the same flask is filled with concentrated sulfuric acid, H2SO4, its mass is 1026.57 g. What is the density of concentrated sulfuric acid? (Assume water has a density of 1.00 g/cm3 at the temperature of the measurement.) Enter NUMBERS ONLY in your answer using units of g cm-3. Please make sure you round to the appropriate number of significant figures.

This is what i did
i set the density of water .996g/cm^3 = 593.63g-78.23g/V

Solved for Volume of water and got 517.469

then to find density of sulfer i divided 1026.57/517.469

and got D= 1.983 g/cm3

Very confused though due to significant figures and roundings, can some one check my answer and correct me if i am wrong?.

This is what i did

i set the density of water .996g/cm^3 = 593.63g-78.23g/V
First, i is I. The original problem lists the density of water as 1.00 g/mL; therefore, you need to correct volume using the proper density value.

Solved for Volume of water and got 517.469
I think the value is closer to 515 something.

then to find density of sulfer i divided 1026.57/517.469
Isn't the mass of H2SO4 1026.57-78.23 = ??

and got D= 1.983 g/cm3
You have 5 s.f. in the water calcn and 3 for the density; therefore, the volume is known to 3 s.f. You can't have more than 3 s.f. in the final answer.

To find the density of concentrated sulfuric acid, you can use the formula:

Density = Mass / Volume

First, calculate the volume of water in the flask. You correctly calculated it as 517.469 cm^3.

Then, use the mass of the concentrated sulfuric acid (1026.57 g) and the volume of water to find the density of sulfuric acid:

Density = 1026.57 g / 517.469 cm^3

Calculating this, the density of concentrated sulfuric acid is approximately 1.989 g/cm^3.

Rounding to the appropriate number of significant figures, the final answer should be reported as 1.99 g/cm^3.

To find the density of concentrated sulfuric acid, you need to calculate the volume of sulfuric acid and then divide the mass of sulfuric acid by the volume.

Let's break down the steps:

Step 1: Calculate the volume of water in the flask.
Given:
- Mass of empty flask = 78.23 g
- Mass of flask filled with water = 593.63 g
- Density of water = 1.00 g/cm³

You correctly set up the equation:
Density of water = mass of water / volume of water

By rearranging the equation, you get:
Volume of water = mass of water / density of water

Volume of water = (593.63 g - 78.23 g) / (1.00 g/cm³) = 515.40 cm³ (rounded to five significant figures)

Step 2: Calculate the density of concentrated sulfuric acid.
Given:
- Mass of flask filled with sulfuric acid = 1026.57 g

Density of sulfuric acid = mass of sulfuric acid / volume of sulfuric acid
Volume of sulfuric acid = volume of flask - volume of water
Volume of sulfuric acid = (1026.57 g - 78.23 g) / (1.00 g/cm³) - 515.40 cm³ = 433.94 cm³ (rounded to five significant figures)

Density of sulfuric acid = 1026.57 g / 433.94 cm³ = 2.369 g/cm³ (rounded to four significant figures)

So, the density of concentrated sulfuric acid is 2.369 g/cm³ (rounded to four significant figures).