what quantity x of a 65% acid solution must be mixed with a 20% solution to produce 300 mL of a 45% solution
Your school subject is not college.
To find the quantity of the 65% acid solution needed, let's break down the problem step by step:
Step 1: Define the variables:
Let's assume that the quantity of the 65% acid solution to be added is 'x' mL.
Step 2: Calculate the quantity of the 20% solution:
Since the total volume of the mixture is 300 mL, the quantity of the 20% solution can be calculated as (300 - x) mL.
Step 3: Set up the equation based on the acid concentration:
Since we want to produce a 300 mL mixture with a 45% acid concentration, we can set up the equation as follows:
0.65x + 0.20(300 - x) = 0.45(300)
Step 4: Solve the equation:
Now, let's solve the equation to find the value of 'x'.
0.65x + 0.20(300 - x) = 0.45(300)
0.65x + 60 - 0.20x = 135
0.45x = 135 - 60
0.45x = 75
x = 75 / 0.45
x ≈ 166.67 mL (rounded to two decimal places)
So, approximately 166.67 mL of the 65% acid solution needs to be mixed with 133.33 mL of the 20% solution to produce 300 mL of a 45% solution.