find the slope and the y intercept of the line. Please help me I keep getting the y intercept wrong.
8x=9y + 54
I got the slope correct but I cant get the y intercept.
8x = 9y + 54.
Put Eq in STD Form:
8x - 9y = 54
The y-Int IS the point where the graph crosses the y-axis and x = 0. Therefore, you should substitute 0 for
x in your STD Eq and solve for y.
8 * 0 - 9y = 54
y = -6 = y-Int.
P(0 , -6).
Slope = -A/B = -8/-9 = 8/9.
Determine the x-intercept and y-intercept of 3x - 6y = 12.(Points : 2)
(9, 0) and (0, -3)
(4, 0) and (0, -2)
(-4, 0) and (0, 4)
To find the slope and y-intercept of a line, we can first convert the equation into slope-intercept form, which is in the form of y = mx + b. In this equation, m represents the slope of the line, and b represents the y-intercept.
Given the equation:
8x = 9y + 54
To convert it into slope-intercept form, we need to isolate y on one side of the equation. Let's rearrange the equation:
9y = 8x - 54
Divide both sides of the equation by 9 to solve for y:
y = (8/9)x - 6
Now, we can see that the equation is in slope-intercept form, y = mx + b. The slope, represented by m, is 8/9, and the y-intercept, represented by b, is -6.
Therefore, the slope of the line is 8/9, and the y-intercept is -6.