trig

find all sets of three consecutive odd integers whose sum is greater than 54 and less than 63

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  1. The sum of three consecutive odd integers is
    S(n)=(n-2) + n + (n+2) = 3n
    So 54<S(n)<63, or
    54 < 3n < 63
    Divide all by 3 to get
    18 < n < 21
    Solve for all valid (integer) value of n.
    Each value of n relates to the set of integers {n-2, n, n+2} that satisfies the specified requirements.

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  2. how do you get n-2, n, n+2 I keep getting n, n+2 and n+4?

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