# Math Word Problem

The length of a rectangle is twice the width. The area is 242 yd^2. Find the length and the width of the rectangle.
The width would be? The length would be?

I am not sure if I am to take 242 and sqrt it to give me 58,564 and then divide by 4 or what. I am lost with this.

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1. L = 2W

L * W = 242

2W * W = 242

Solve for W, then L.

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2. So the L=242 and the W=60.5

Or am I way off base with this?

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3. Or would the L=484 and the W=242

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4. no, work out PsyDAG's equation.

2W*W = 242
W^2 = 121
W = √121 = 11

so W = 11
L = 2W = 22

Check:
Area = 11*22 = 242

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5. 6+6

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6. The area of a rectangle is
99 ft2
, and the length of the rectangle is
7 ft
more than twice the width. Find the dimensions of the rectangle.

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