Math 208

Graph y<2x+2

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asked by Jackie
  1. Graph Y < 2X + 2. First, we graph the
    boundary line which always uses an equal sign: Y = 2X + 2. Since there's no = sign in the inequality, the boundary line should be a dotted line.
    Select 2 or 3 convenient points:
    (0 , 2) , (-1 , 0) , (2 , 6). The 1st 2 points are the Y and X - Intercepts.
    The points on the dotted line should
    not satisfy the inequality. Let's test
    the 1st point: 2 < 2*0 + 2, 2 < 2 is
    not a true statement. Therefore, the
    point does not satisfy the inequality.
    The solution is either all points below the line or all points above
    the line. Let's test a point below
    the line: Try (0 , 0).0 < 2*0 + 2,
    0 < 2 is a true statement. So ALL
    points below the line are part of the
    solution and should satisfy the in-
    equality. ALL of the area below the
    line is normally shaded.

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    posted by Henry

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