# cartesian vectors 1

Given that points P(-6,1), Q(-2, -1) and R(-3,4) find:
a) magnitude of vector RP
b) perimeter of triangle PQR

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1. GIVEN: P(-6 , 1) , Q(-2 , -1) ,
R(-3 , 4).

a. (RP)^2 = (-3 + 6)^2 + (4 - 1) =
9 + 9 = 18,
RP = sqrt(18) = 3*sqrt(2) = 4.24.

b. (PQ)^2 = (-2 + 6)^2 + (-1 , -1)^2 =
= 16 + 4 = 20,
PQ = 2*sqrt(5) = 4.47

(QR)^2 = (-3 + 2)^2 + (4 - 1)^2
= 10,
QR = sqrt(10) = 3.16.

P = PQ + QR + RP = 4.47 + 3.16
+ 4.24 = 11.87 = Perimeter.

NOTE. The distance fohmula is used to cal. the length of each side.

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posted by Henry

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